Find ceiling value of a number using Math.ceil
- /*
- Find ceiling value of a number using Math.ceil
- This java example shows how to find a ceiling value of a number using ceil method
- of Java Math class. ceil method returns the smallest interger which is not
- less than the value.
- */
- public class FindCeilingExample {
- public static void main(String[] args) {
- /*
- * To find a ceiling value, use
- * static double ceil(double d) method of Math class.
- *
- * It returns a smallest integer which is not less than the argument value.
- */
- //Returns the same value
- System.out.println(Math.ceil(10));
- //returns a smallest integer which is not less than 10.1, i.e. 11
- System.out.println(Math.ceil(10.1));
- //returns a smallest integer which is not less than 5.5, i.e. 6
- System.out.println(Math.ceil(5.5));
- //in this case it would be -20
- System.out.println(Math.ceil(-20));
- //it returns -42 not -43. (-42 is grater than 42.4 :) )
- System.out.println(Math.ceil(-42.4));
- //returns 0
- System.out.println(Math.ceil(0));
- }
- }
- /*
- Output would be
- 10.0
- 11.0
- 6.0
- -20.0
- -42.0
- 0.0
- */



